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(B) The relationship between the maximum electric field $(E_0)$ and the maximum magnetic field $(B_0)$ in an electromagnetic wave is given by the equa

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$3 	imes 10^4 \, N/C$

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(B) The relationship between the maximum electric field $(E_0)$ and the maximum magnetic field $(B_0)$ in an electromagnetic wave is given by the equation:$E_0 = B_0 	imes c$From the given equation of the magnetic field,the amplitude $B_0$ is:$B_0 = 100 	imes 10^{-6} \, T$The speed of light $c$ is given as:$c = 3 	imes 10^8 \, m/s$Substituting these values into the formula:$E_0 = (100 	imes 10^{-6}) 	imes (3 	imes 10^8)$$E_0 = 100 	imes 3 	imes 10^{8-6}$$E_0 = 300 	imes 10^2$$E_0 = 3 	imes 10^4 \, N/C$

If the magnetic field of a plane electromagnetic wave is given by (The speed of light $c = 3 \times 10^8 \, m/s$):
$B = 100 \times 10^{-6} \sin \left[ 2\pi \times 2 \times 10^{15} \left( t - \frac{x}{c} \right) \right]$
Then the maximum electric field associated with it is:

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If the magnetic field of a plane electromagnetic wave is given by (The speed of light $c = 3 \times 10^8 \, m/s$):$B = 100 \times 10^{-6} \sin \left[ 2\pi \times 2 \times 10^{15} \left( t - \frac{x}{c} \right) \right]$Then the maximum electric field associated with it is: